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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) the area of the parallelogram PQRS
(b) QN, if PS = 8 cm
Solution:
(a) SR = 12 cm and QM = 7.6 cm.
Area of parallelogram PQRS = Base × Height
= SR × QM
= 12 cm × 7.6 cm
= 91.2 cm2
(b) Base = PS = 8 cm
Area of the parallelogram = 91.2 cm2 [calculated in part (a)]
Area of parallelogram PQRS = Base × Height
91.2 cm2 = 8 cm × QN
QN = 91.2 cm2 / 8 cm
QN = 11.4 cm
☛ Check: NCERT Solutions for Class 7 Maths Chapter 11
Video Solution:
PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find: (a) the area of the parallelogram PQRS (b) QN, if PS = 8 cm
Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.2 Question 5
Summary:
PQRS is a parallelogram. QM is the height of Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Then: (a) The area of the parallelogram PQRS is 91.2 cm2 (b) QN is 22.8 cm, if PS = 8 cm
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