Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation. (a) 5m = 60 (10, 5, 12, 15) (b) n + 12 = 20 (12, 8, 20, 0) (c) p – 5 = 5 (0, 10, 5 – 5) (d) q / 2 = 7 (7, 2, 10, 14) (e) r – 4 = 0 (4, -4, 8, 0) (f) x + 4 = 2 (-2, 0, 2, 4)
Solution:
We will use the concepts of algebra and the basic of algebra to answer the given questions.
(a) 5m = 60
m = 12 is a solution for this equation because for m = 12, 5m = 5 × 12 = 60
m = 10 is not a solution for this equation because for m = 10, 5m = 5 × 10 = 50 and not 60
m = 5 is not a solution for this equation because for m = 5, 5m = 5 × 5 = 25 and not 60
m = 15 is not a solution for this equation because for m = 15, 5m = 5 × 15 = 75 and not 60
(b) n + 12 = 20
n = 8 is a solution for this equation because for n = 8, n + 12 = 8 + 12 = 20
n = 12 is not a solution for this equation because for n = 12, n + 12 = 12 + 12 = 24 and not 20
n = 20 is not a solution for this equation because for n = 20, n + 12 = 20 + 12 = 32 and not 20
n = 0 is not a solution for this equation because for n = 0, n + 12 = 0 + 12 = 12 and not 20
(c) p – 5 = 5
p = 10 is a solution for this equation because for p = 10, p – 5 = 10 – 5 = 5
p = 0 is not a solution for this equation because for p = 0, p – 5 = 0 – 5 = -5 and not 5
p = 5 is not a solution for this equation because for p = 5, p – 5 = 5 – 5 = 0 and not 5
p = -5 is not a solution for this equation because for p = -5, p – 5 = -5 – 5 = – 10 and not 5
(d) q / 2 = 7
q = 14 is a solution for this equation because for q = 14, q / 2 = 14 / 2 = 7
q = 7 is not a solution for this equation because for q = 7, q / 2 = 7 / 2 and not 7
q = 2 is not a solution for this equation because for q = 2, q / 2 = 2 / 2 = 1 and not 7
q = 10 is not a solution for this equation because for q = 10, q / 2 = 10 / 2 = 5 and not 7
(e) r – 4 = 0
r = 4 is a solution for this equation because for r = 4, r – 4 = 4 – 4 = 0
r = -4 is not a solution for this equation because for r = – 4, r – 4 = – 4 – 4 = -8 and not 0
r = 8 is not a solution for this equation because for r = 8, r – 4 = 8 – 4 = 4 and not 0
r = 0 is not a solution for this equation because for r = 0, r – 4 = 0 – 4 = – 4 and not 0
(f) x + 4 = 2
x = -2 is a solution for this equation because for x = -2, x + 4 = – 2 + 4 = 2
x = 0 is not solution for this equation because for x = 0, x + 4 = 0 + 4 = 4 and not 2
x = 2 is not a solution for this equation because for x = 2, x + 4 = 2 + 4 = 6 and not 2
x = 4 is not a solution for this equation because for x = 4, x + 4 = 4 + 4 = 8 and not 2
NCERT Solutions for Class 6 Maths Chapter 11 Exercise 11.5 Question 3
Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation. (a) 5m = 60 (10, 5, 12, 15) (b) n + 12 = 20 (12, 8, 20, 0) (c) p – 5 = 5 (0, 10, 5 – 5) (d) q / 2 = 7 (7, 2, 10, 14) (e) r – 4 = 0 (4, -4, 8, 0) (f) x + 4 = 2 (-2, 0, 2, 4)
Summary:
(a) 5m = 60 is only satisfied by m=12 and not by m=10, m=5 or m=15 (b) n + 12 = 20 is only satisfied by n=8 and not by n=12 , n=20 or n=0 (c) p – 5 = 5 is only satisfied by p=10 and not by p=0, p=5 or p= -5 (d) q / 2 = 7 is only satisfied by q=14 and not by q=7, q=2 or q=10 (e) r – 4 = 0 is only satisfied by r=4 and not by r= -4, r= 8 or r= 0 (f) x + 4 = 2 is only satisfied by x= -2 and not by x=0, x=2 or x=4
☛ Related Questions:
- State Which Of The Following Are Equations With A Variable Give Reason For Your Answer Identify The Variable From The Equations With A Variablea 17 X 17 Is An Algebraic Equation
- Complete The Entries In The Third Column Of The Table Sno Equation Value Of Variable Equation Satisfied Yes No A 10y 80 Y 10 B 10y 80 Y 8 C 10y 80 Y 5 D 4l 20 L 20
- Acomplete The Table And By Inspection Of The Table Find The Solution To The Equation M 10 16 B Complete The Table And By Inspection Of The Table Find The Solution To The
- Solve The Following Riddles You May Yourself Construct Such Riddles Who Am I I Go Round A Square Counting Every Corner Thrice And No More Add The Count To Me To Get Exactly
visual curriculum