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Physical Science Application: Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true:

The child on the left and child on the right are balanced. What is the mass of the child on the right

Solution:

Two children can be balanced on a seesaw.

Given, the condition for balancing unequal masses is

Mass 1 / Length 2 = Mass 2 / Length 1

We have to find the mass of the child on the right.

From the figure,

Mass 1 = 24 kg

Length 1 = 3 m

Length 2 = 2 m

Now, 24/2 = Mass 2 / 3

12 = Mass 2 / 3

Mass 2 = 12(3)

Mass 2 = 36 kg

Therefore, the required mass is 36 kg.

✦ Try This: In a meseum, the entrance ticket costs Rs. 250. In Vacation, the cost of the ticket is reduced, there by increasing the sale by 50 %, but it was found that the collection is decreased by 17.5 %. What is the deduction in the ticket price?

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 8

NCERT Exemplar Class 7 Maths Chapter 7 Problem 117(b)

Physical Science Application: Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down. Unequal masses will balance when the following proportion is true

Summary:

Two children can be balanced on a seesaw. The child on the left and child on the right are balanced. The mass of the child on the right is 36 kg.

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