One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Solution:

Let the digit at tens place be x.

Then the digit at ones place will be 3x.

Original two-digit number = 10x + 3x

After interchanging the digits, the new number = 10(3x) + x = 30x + x

According to the question,

New number + Original number = 88

(30x + x) + (10x + 3x) = 88

⇒ 31x + 13x = 88

⇒ 44x = 88

Dividing both sides by 44, we obtain

x = 2

Thus, 3x = 6

Therefore, original number = 26

☛ Check: NCERT Solutions for Class 8 Maths Chapter 2

Video Solution:

One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.4 Question 4

Summary:

One of the two digits of a two-digit number is three times the other digit. If we interchange the digits of this two-digit number and add the resulting number to the original number, we get 88. The original number is 26.

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