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NCERT Solutions Class 8 Maths Chapter 11 Exercise 11.3 Mensuration

NCERT solutions for class 8 maths chapter 11 exercise 11.3 mensuration now introduces a brand new concept of surface areas. The solid or 3D shapes used are cubes, cuboids, and cylinders. The total surface area can be defined as the summation of all the faces of a solid surface. An interesting fact that kids come across is that these surface areas formulas are derived from plane figures. This implies that kids must have an in-depth knowledge of the shapes seen in the earlier exercises to solve these problems. There are 10 problems in the NCERT solutions class 8 maths chapter 11 exercise 11.3. The level of difficulty ranges from simple to medium-level sums.

The important skill that kids need to have to attempt this exercise is that of visualizing shapes. The intermediate sums can be tricky and require kids to modulate the formulas in a way to suit the question. For example, a problem might ask a kid to cover only the 4 faces of a cube with paper not including the roof and floor thus, kids need to modify the formula to get the result. The class 8 maths NCERT solutions chapter 11 exercise 11.3 mensuration show students how to solve such sums and can be found below in a scrollable pdf format.

☛ Download NCERT Solutions Class 8 Maths Chapter 11 Exercise 11.3

Exercise 11.3 Class 8 Chapter 11

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More Exercises in Class 8 Maths Chapter 11

NCERT Solutions Class 8 Maths Chapter 11 Exercise 11.3 Tips

NCERT solutions class 8 maths chapter 11 exercise 11.3 mensuration has three important total surface area formulas.

TSA of a cuboid = 2(lb + bh + hl). A cuboid is made up of 6 faces that are rectangular in shape. As the area of a rectangle is given by length * breadth, the same concept is used to derive this particular surface area formula. We first find the area of each individual rectangular plate and sum it up to get the result.
TSA of a cube = 6a². a is the length of the side. As a cube is made up of 6 squares, we first find the area of each square given by a² and sum it up 6 times to get the result.
TSA of a cylinder = 2πr (r + h). The curved surface area of a cylinder is given by 2πrh (multiplying height with the perimeter of a circle). It is also enclosed by two circles on the top and bottom given by πr². We sum this up to get the formula.

NCERT solutions class 8 maths chapter 11 exercise 11.3 gives a general idea of solving problems that makes use of such concepts. It helps students improve their speed and accuracy in calculations while gaining reasoning abilities.

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NCERT Video Solutions for Class 8 Maths Chapter 11 Exercise 11.3

Video Solutions for Class 8 Maths Chapter 11 Exercise 11.3
Exercise 11.3 Question 1	Exercise 11.3 Question 6
Exercise 11.3 Question 2	Exercise 11.3 Question 7
Exercise 11.3 Question 3	Exercise 11.3 Question 8
Exercise 11.3 Question 4	Exercise 11.3 Question 9
Exercise 11.3 Question 5	Exercise 11.3 Question 10

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