NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.3 Arithmetic Progressions
NCERT solutions for class 10 maths chapter 5 exercise 5.3 Arithmetic Progressions will help students learn how to calculate the sum of the first ‘n’ terms of an arithmetic progression by using the formula n/2 [ 2a + (n-1)d ] where 'a' is the first term and ‘d’ is the common difference. They will also uncover the formula, where S = n/2(a+l), if the first term (a) and the last term (l) is given and the common difference is not known.
The nth term of an AP can be said to be the difference of the total of first ‘n’ terms and the total of the first (n – 1) terms, i.e., an = Sn – Sn – 1
This NCERT solutions ex 5.3 class 10 math has 20 detailed questions which aim at covering and exploring all the different possible cases of arithmetic progressions. The pdf of the exercise questions in the class 10 maths NCERT solutions chapter 5 exercise 5.3 is given below :
☛ Download NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.3
Exercise 5.3 Class 10 Chapter 5
More Exercises in Class 10 Maths Chapter 5
- NCERT Solutions Class 10 Maths Chapter 5 Ex 5.1
- NCERT Solutions Class 10 Maths Chapter 5 Ex 5.2
- NCERT Solutions Class 10 Maths Chapter 5 Ex 5.4
NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.3 Tips
NCERT solutions class 10 maths chapter 5 exercise 5.3 Arithmetic Progressions will assist the students in calculating the sum of ‘n’ terms of an AP. For this, we need the values of the first term and the total number of terms. The students must remember that the following formulas to find the sum of an arithmetic progression:
- Sn = n/2 * [2a + (n−1) d], where 'a' is the first term and 'd' is the common difference
- Sn = n/2 * (a + l), where 'a' is the first term and 'l' is the last term
NCERT solutions class 10 maths chapter 5 exercise 5.3 includes questions that can be a bit complex, but students should ensure that they explore the solved examples before practising this exercise. They can always refer to the highlights in the NCERT textbook to clear their doubts.
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NCERT Class 10 Maths Video Solutions Chapter 5 Exercise 5.3
| NCERT Videos for Class 10 Maths Chapter 5 Exercise 5.3 | |
|---|---|
| Question 1 | Question 11 |
| Question 2 | Question 12 |
| Question 3 | Question 13 |
| Question 4 | Question 14 |
| Question 5 | Question 15 |
| Question 6 | Question 16 |
| Question 7 | Question 17 |
| Question 8 | Question 18 |
| Question 9 | Question 19 |
| Question 10 | Question 20 |
FAQs on Ex 5.3 Class 10
What is Ex 5.3 Class 10 All About?
Ex 5.3 class 10 deals with the sum of 'n' terms of AP. It uses two formulas to calculate the sum: Sn = n/2 * [2a + (n−1) d] and Sn = n/2 * (a + l). Here, a and l are the first and the last terms respectively, whereas d is the common difference.
How Many Questions Does Class 10th Math Ex 5.3 Have?
Class 10 ex 5.3 has 20 questions where some questions are involved with subparts:
- Question 1 is the application of the sum formula Sn = n/2 * [2a + (n−1) d].
- Question 2 is the application of the sum formula Sn = n/2 * (a + l).
- Question 3 has 10 subparts where one of the terms first term, last term, n, or sum is missing.
- Questions 4 to question 20 are word problems kinds using the sum formula of AP.
Is Class 10 Maths Chapter 5 Exercise 5.3 Easy?
Class 10 maths chapter 5 exercise 5.3 is a bit challenging as the students need to understand the concept of sum of AP first and apply it in different ways. This exercise also involves students' expertise in performing calculations.
What Should the Students Practice Before Doing Ex 5.3 Class 10?
Before doing ex 5.3 class 10 math, students should first practice the previous two exercises 5.1 and 5.2.
- Exercise 5.1 deals with the definition of arithmetic progression and common difference.
- Exercise 5.2 deals with the nth term of AP.