NCERT Solutions Class 10 Maths Chapter 13 Surface Area and Volumes

NCERT solutions for class 10 maths chapter 13 Surface Area and Volumes helps students revise several solid shapes like cube, cone, cylinder, cuboid, etc., along with the formulas of surface area and volume of these solid figures that they have learned in the previous classes. These concepts are a part of our everyday life; hence it is important to understand these solids and their properties. Class 10 maths NCERT solutions chapter 13 Surface Area and Volumes will further illustrate the surface area and volume of these solids in combination. This means that through this chapter, students will learn how to calculate the surface area and volume of two or more solid shapes combined together.

NCERT solutions class 10 maths chapter 13 will help students explore several topics such as surface area and volume of combination solids, conversion of solid from one shape to another, and frustum of a cone. This chapter has a variety of questions based on different shapes and their combinations. The questions are curated by experts; hence each and every sum will benefit students by helping them explore a lot of distinct concepts. We will study this chapter further with the help of this article and also you can find some of these in the exercises given below.

• NCERT Solutions Class 10 Maths Chapter 13 Ex 13.1
• NCERT Solutions Class 10 Maths Chapter 13 Ex 13.2
• NCERT Solutions Class 10 Maths Chapter 13 Ex 13.3
• NCERT Solutions Class 10 Maths Chapter 13 Ex 13.4
• NCERT Solutions Class 10 Maths Chapter 13 Ex 13.5

NCERT Solutions for Class 10 Maths Chapter 13 PDF

NCERT solutions maths for class 10 offer optimal coverage of various topics related to different shapes and figures. These topics are explained in detail with examples. You can practice all the exercise questions of this chapter using the PDF given below:

☛ Download Class 10 Maths NCERT Solutions Chapter 13

NCERT Class 10 Maths Chapter 13  Download PDF

NCERT Solutions for Class 10 Maths Chapter 13 Surface Area and Volumes

Class 10 NCERT solutions chapter 13 Surface Area and Volume includes all important questions and their solutions that are prepared by the experts. The chapter deals with different shapes as well as the combination of these shapes. This section has a lot of real-life applications hence, students can easily relate to it. The detailed analysis of NCERT Solutions Chapter 13 Surface Area and Volumes are given below:

• Class 10 Maths Chapter 13 Ex 13.1 - 9 Questions
• Class 10 Maths Chapter 13 Ex 13.2 - 8 Questions
• Class 10 Maths Chapter 13 Ex 13.3 - 9 Questions
• Class 10 Maths Chapter 13 Ex 13.4 - 5 Questions
• Class 10 Maths Chapter 13 Ex 13.5 - 7 Questions

☛ Download Class 10 Maths Chapter 13 NCERT Book

Topics Covered: The important topics covered in class 10 maths NCERT solutions Chapter 13 are the surface area of solid shapes, combination solids, the volume of solid shapes, combination solids, conversion of solid from one shape to another, and frustum of a cone.

Total Questions: Class 10 Maths Chapter 13 Surface Area and Volumes consists of 38 questions. Out of these 38 problems, 18 are easy to solve, 10 are moderate level sums, while the other ten are in long answer type format.

List of Formulas in NCERT Solutions Class 10 Maths Chapter 13

NCERT solutions class 10 maths Chapter 13 are competent resources for class 10 maths that cover fundamental concepts of chapter 13 Surface Area and Volumes. This chapter is all about formulas. Hence, there is a long list of important formulas that students need to remember in order to solve all questions.

Surface Area of a cuboid of length l, breadth b, and height h = 2 (l ✕ b+ b ✕ h+ l ✕ h)

 Lateral Surface Area of cuboid = 2 ( l+ b) h

Surface Area of a cube = 6 l² where l is the length

Lateral Surface Area of cube = 4 l² where l is the length

Volume of cube = l³

Lateral Surface Area of a Cylinder = 2πrh

Total Surface Area of a Cylinder = 2πr (h+r)

Volume of Cylinder = πr² h

Lateral Surface Area of Cone = πrL

Total surface area of cone = πr ( L+ r)

Volume of Cone = ⅓ (πr² h)

Surface Area of Sphere= 4 πr²

Volume of Sphere = 4/3 (πr³)

Volume of Frustum of cone = 1/3 πh ( r²_{1 +} r²₂+ r_{1 +} r₂)

Total Surface Area of Frustum of cone = πL( r_{1 +} r₂)+π(r²₁ + r²₂)

Important Questions for Class 10 Maths NCERT Solutions Chapter 13

Video Solutions for Class 10 Maths NCERT Chapter 13