Narain bought 120 oranges at ₹4 each. He sold 60 % of the oranges at ₹5 each and the remaining at ₹3.50 each. His ________ is ________%. Fill in the blanks to make the statement true.
Solution:
Narain bought 120 oranges at ₹4 each. He sold 60 % of the oranges at ₹5 each and the remaining at ₹3.50 each. His ________ is ________%.
We have to fill in the blanks to make the statement true.
According to the question,
CP of 1 oranges = ₹4
CP of 120 oranges = 4 ×120 = ₹480
60% of 120 = (60/100) 120
= 6 12
= 72
SP of 72 oranges = 5 × 72 = ₹360
Remaining oranges = 120 - 72 = 48
SP of 48 oranges = 3.50 × 48 = ₹168
SP of 120 oranges = 360 + 168 = ₹528
Since SP > CP, it is profit
We know, Profit = SP - CP
= 528 - 480
Profit = ₹48
We know, Profit% = Profit/CP × 100
= 48/480 × 100
= 4800/480
= 10%
Therefore, the profit is 10%
✦ Try This: Ramesh bought 100 apples at ₹5 each. He sold 70 % of the oranges at ₹7 each and the remaining at ₹8 each. His ________ is ________%. Fill in the blanks to make the statement true.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 8
NCERT Exemplar Class 7 Maths Chapter 7 Problem 45
Narain bought 120 oranges at ₹4 each. He sold 60 % of the oranges at ₹5 each and the remaining at ₹3.50 each. His ________ is ________%. Fill in the blanks to make the statement true
Summary:
Narain bought 120 oranges at ₹4 each. He sold 60 % of the oranges at ₹5 each and the remaining at ₹3.50 each. His profit is 10%.
☛ Related Questions:
- A fruit seller purchased 20 kg of apples at ₹50 per kg. Out of these, 5% of the apples were found to . . . .
- Interest on ₹3000 at 10% per annum for a period of 3 years is ________. Fill in the blanks to make t . . . .
- Amount obtained by depositing ₹20,000 at 8 % per annum for six months is ________. Fill in the blank . . . .
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