My younger sister's age today is 3 times, what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age
Solution:
Let the present age of her be x years
Then after 3 years, her age be (x + 3) years and 3 years ago her age would be (x - 3) years
The linear equation formed is:
x = 3 [(x + 3) - (x - 3)]
x = 3 [x + 3 - x + 3]
x = 3 [6]
x = 18
Thus, her present age is 18 years.
✦ Try This: My brother's age today is 2 times, what it will be 2 years from now minus 2 times what her age was 2 years ago. Find his present age.
Let his present age be x years
Then after 2 years, his age be (x + 2) years and 2 years ago his age would be (x - 2) years
A/Q
x = 2 [(x + 2) - (x - 2)]
x = 2 [x + 2 - x + 2]
x = 2 [4]
x = 8
Thus, his present age is 8 years.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 4
NCERT Exemplar Class 7 Maths Chapter 4 Problem 79
My younger sister's age today is 3 times, what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age
Summary:
If my younger sister's age today is 3 times the age after 3 years minus 3 times her age 3 years ago, then her present age is 18 years
☛ Related Questions:
visual curriculum