Match each of the entries in Column I with the appropriate entries in Column II:
Column I Column II
(i) 3:5 (A) ₹ 54
(ii) 2.5 (B) ₹ 47\
(iii) 100% (C) ₹ 53
(iv) 2/3 (D) ₹ 160
(v) 6 1/4% (E) 60 %
(vi) 12.5 % (F) 25 %
(vii) SP when CP = ₹50 and loss = 6 % (G) 1/16
(viii) SP when CP = ₹50 and profit = ₹4 (H) 250 %
(ix) Profit% when CP = ₹40 and SP = ₹50 (I) ₹ 159
(x) Profit% when CP = ₹50 and SP = ₹60 (J) 66 2/3 %
(xi) Interest when principal = ₹800,Rate of
interest = 10% per annum and period = 2 yrs (K) 20 %
(xii) Amount when principal = ₹150,
rate of interest = 6% per annum
and period = 1 yr (L) 0. 125
(M) 3 : 2
(N) ₹ 164
(O) 3 : 3
Solution:
We have to match each of the entries in Column I with the appropriate entries in Column II.
(i) 3:5
In percentage, 3:5 = 3/5 × 100
= 3(20)
= 60% (E)
(ii) 2.5
In percentage, 2.5 × 100 = 250% (H)
(iii) 100%
Ratio = 100/100 : 1
= 1 : 1
Multiplying by 3 on both sides,
= 3 : 3 (O)
(iv) 2/3
In percentage, 2/3 × 100
= 200/3
= 66 2/3 % (J)
(v) 6 1/4 %
6 1/4 = 25/4%
In fraction, (25/4) / 100 = 25/400 = 1/4 (G)
(vi) 12.5%
In fraction, 12.5/100 = 0.125 (L)
(vii) SP when CP = ₹50 and loss = 6 %
SP = 50 - 6% of 50
= 50 - (6/100) × 50
= 50 - 6/2
= 50 - 3
SP = ₹47 (B)
(viii) SP when CP = ₹50 and profit = ₹4
We know, Profit = SP - CP
4 = SP - 50
SP = ₹54 (A)
(ix) Profit% when CP = ₹40 and SP = ₹50
Profit = SP - CP
= 50 - 40
= ₹10
Profit% = Profit/CP × 100
= 10/40 × 100
= 100/4
= 25% (F)
(x) Profit% when CP = ₹50 and SP = ₹60
Profit = SP - CP
= 60 - 50
= ₹10
Profit% = Profit/CP × 100
= 10/50 × 100
= 100/5
= 20% (K)
(xi) Interest when principal = ₹800, Rate of interest = 10% per annum and period = 2 years
We know, I = P × R × T/100
I = 800 × 10 × 2 / 100
= 8 × 20
= ₹160 (D)
(xii) Amount when principal = ₹150, Rate of interest = 6% per annum and period = 1 year
We know, I = P × R × T/100
I = 150 × 6 × 1 / 100
= 15 × 6/10
= 3 × 3
= ₹9
We know, A = P + I
A = 150 + 9 = ₹159 (I)
✦ Try This: The Selling price of 3 aticles is equal to the cost price of 4 articles. Find the profit percentage.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 8
NCERT Exemplar Class 7 Maths Chapter 7 Problem 129
Match each of the entries in Column I with the appropriate entries in Column II: Column I Column II (i) 3:5 (A) ₹ 54 (ii) 2.5 (B) ₹ 47 (iii) 100% (C) ₹ 53 (iv) 2/3 (D) ₹ 160 (v) 6 1/4% (E) 60 % (vi) 12.5 % (F) 25 % (vii) SP when CP = ₹50 and loss = 6 % (G) 1/16 (viii) SP when CP = ₹50 and profit = ₹4 (H) 250 % (ix) Profit% when CP = ₹40 and SP = ₹50 (I) ₹ 159 (x) Profit% when CP = ₹50 and SP = ₹60 (J) 66 2/3 % (xi) Interest when principal = ₹800, Rate of interest = 10% per annum and period = 2 yrs (K) 20 % (xii) Amount when principal = ₹150, rate of interest = 6% per annum and period = 1 yr (L) 0. 125 (M) 3 : 2 (N) ₹ 164 (O) 3 : 3
Summary:
(i) 3:5 → (E) 60%, (ii) 2.5 → (H) 250%, (iii) 100% → (O) 3 : 3, (iv) 2/3 → (J) 66 2/3 %, (v) 6 1/4% → (G) 1/16, (vi) 12.5 % → (L) 0.125, (vii) SP when CP = ₹50 and loss = 6 % → (B) ₹47, (viii) SP when CP = ₹50 and profit = ₹4 → (A) ₹54, (ix) Profit% when CP = ₹40 and SP = ₹50 → (F) 25%, (x) Profit% when CP = ₹50 and SP = ₹60 → (K) 20 %, (xi) Interest when principal = ₹800,Rate of interest = 10% per annum and Period 2 yrs → (D) ₹160, (xii) Amount when principal = ₹150, rate of interest = 6% per annum and period = 1 yr → (I) ₹159
☛ Related Questions:
- In a debate competition, the judges decide that 20 percent of the total marks would be given for acc . . . .
- Divide ₹10000 in two parts so that the simple interest on the first part for 4 years at 12 percent p . . . .
- ₹9000 becomes ₹18000 at simple interest in 8 years. Find the rate per cent per annum
visual curriculum