Look at the several examples of rational numbers in the form p/q (q ≠ 0), where p and q are integers with no common factors other than 1 and having terminating decimal representations (expansions). Can you guess what property q must satisfy?
Solution:
We shall look at some examples of rational numbers in the form of p/q (q ≠ 0), where their decimal representations are terminating.
2/5 = 0.4
3/100 = 0.03
27/16 = 1.6875
33/50 = 0.66
Let's observe the denominators of the above rational numbers.
2/5 = 2 / (20 × 51)
3/100 = 3 / (22 × 52)
27/16 = 27 / (24 × 50)
33/50 = 33 / (21 × 52)
We observe that the denominators of the above rational numbers are in the form of 2a × 5b, where a and b are whole numbers.
Hence if q is in the form 2a × 5b then p/q is a terminating decimal.
☛ Check: Class 9 Maths NCERT Solutions for Chapter 1
Video Solution:
Look at the several examples of rational numbers in the form p/q (q ≠ 0), where p and q are integers with no common factors other than 1 and having terminating decimal representations (expansions). Can you guess what property q must satisfy?
NCERT Solutions Class 9 Maths Chapter 1 Exercise 1.3 Question 6:
Summary:
The property that q must satisfy to be a terminating decimal in the form of p/q (q ≠ 0), where p and q are integers with no common factors other than 1 is that q must be in the form of 2a × 5b where a and b are whole numbers.
☛ Related Questions:
- You know that 1/7 = 0.142587. Can you predict what the decimal expansions of 2/7, 3/7, 4/7, 5/7, 6/7 are, without actually doing the long division? If so, how?
- Express the following in the form of p/q, where p and q are integers and q ≠ 0. i) 0.6 ii) 0.47 iii) 0.001
- Express 0.99999 .... in the form of p/q. Are you surprised with your answer? With your teacher and classmates discuss why the answer makes sense?
- What can be the maximum number of digits be in the repeating block of digits in the decimal expansion of 1/17? Perform the division to check your answer.
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