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Jaidev takes \(2{\dfrac{1}{5}}\) minutes to walk across the school ground. Rahul takes 7/4 minutes to do the same. Who takes less time and by what fraction?

Solution:

We will use the concepts of fractions to solve this.

Time taken by Jaidev to walk across the school ground = \(2{\dfrac{1}{5}}\)min

Since the given fraction is in the mixed form we need to change to an improper fraction.

= (\(2{\dfrac{1}{5}}\)) = (2×5+1)/5

= 11/5 mins

Time taken by Rahul to walk across the school ground is 7/4min

Let us compare both the fractions, by converting them into an equivalent fraction.

LCM of 5 and 4 is 20

⇒ 11 / 5 = 11 × 4 / 5 × 4 = 44 / 20

⇒ 7 / 4 = 7 × 5 / 4 × 5 = 35 / 20

Since the denominator is the same for both, comparing numerators

44 > 35

Fraction with larger value of numerator will be greater

⇒ 11 / 5 > 7 / 4

So Rahul takes less time than Jaidev.

The difference between both the fractions will give the required value = 11 / 5 - 7 / 4

= 44 / 20 - 35 / 20 = 9 / 20min

Hence, Rahul takes 9/20 mins less than Jaidev to walk across the school ground.

You can also use the Fraction Calculator to check your answer.

NCERT Solutions for Class 6 Maths Chapter 7 Exercise 7.6 Question 9

Summary:

Rahul takes less time than Jaidev to walk across the school ground by a fraction of 9/20 mins.

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