In Fig. 8.13, find tan P – cot R.

Solution:

We use the basic formula for tan and cot to solve the question.

Now, here, we have hypotenuse PR = 13 cm, and side PQ = 12 cm.

Now, from the pythagoras theorem, we have

PQ² + QR² = PR²

So, we have,

QR = √(PR² - QR²)

= √(13² - 12²)

= √25 = 5 cm

We know that, cot R = adjacent side of ∠R / opposite side of ∠R

tan P = opposite side of ∠P / adjacent side of ∠P 

Hence, we have cot R = QR/PQ = 5/12

Also, tan P = QR/PQ = 5/12

So, tan P - cot R = 5/12 - 5/12 = 0

☛ Check: NCERT Solutions for Class 10 Maths Chapter 8

Video Solution:

In Fig. 8.13, find tan P – cot R.

Maths NCERT Solutions Class 10 Chapter 8 Exercise 8.1 Question 2

Summary:

We see that in Fig. 8.13, tan P - cot R = 5/12 - 5/12 = 0.

☛ Related Questions:

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