If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a

Solution:

Given, the equation is 3y = ax + 7

The point (3, 4) lies on the graph

We have to find the value of a.

Since the point (3, 4) lies on the graph, it is clear that the given point will satisfy the equation.

Put x = 3 and y = 4 in the equation,

3(4) = a(3) + 7

12 = 3a + 7

3a = 12 - 7

3a = 5

a = 5/3

Therefore, the value of a is 5/3.

✦ Try This: If the point (2, 5) lies on the graph of 5y = ax + 10, then find the value of a.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4

NCERT Exemplar Class 9 Maths Exercise 4.3 Problem 6

If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a

Summary:

The general form of the linear equation in slope intercept form is y = mx + c. If the point (3, 4) lies on the graph of 3y = ax + 7, then the value of a is 5/3

☛ Related Questions:

• How many solution(s) of the equation 2x + 1 = x - 3 are there on the: (i) Number line, (ii) Cartesia . . . .
• Find the solution of the linear equation x + 2y = 8 which represents a point on (i) x-axis, (ii) y-a . . . .
• For what value of c, the linear equation 2x + cy = 8 has equal values of x and y for its solution