If the coordinates of the two points are P (–2, 3) and Q(–3, 5), then (abscissa of P) – (abscissa of Q) is
a. – 5
b. 1
c. – 1
d. – 2

Solution:

The two coordinate points given are P (–2, 3) and Q(–3, 5)

We know that

Abscissa of point P = -2

Abscissa of point Q = -3

We have to find (abscissa of P) – (abscissa of Q)

Substituting the values

(abscissa of P) – (abscissa of Q) = -2 - (-3)

= -2 + 3

= 1

Therefore, (abscissa of P) – (abscissa of Q) is 1.

✦ Try This: Point (1, 1) lies a. on the x –axis b. in the first quadrant c. on the y-axis d. in the fourth quadrant

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 3

NCERT Exemplar Class 9 Maths Exercise 3.1 Problem 15

If the coordinates of the two points are P (–2, 3) and Q(–3, 5), then (abscissa of P) – (abscissa of Q) is a. – 5 b. 1 c. – 1 d. – 2

Summary:

If the coordinates of the two points are P (–2, 3) and Q(–3, 5), then (abscissa of P) – (abscissa of Q) is 1

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