Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

Solution:

We know that the distance between the two points is given by the Distance Formula = √[( x₂ ^_- x₁ )² + (y₂ - y₁)²]

By substituting the values of points P (2, - 3) and Q (10, y) in the distance formula, we get

PQ = √(2 - 10)² + (- 3 - y)² = 10

PQ = √(- 8)² + (3 +  y)² = 10

Squaring on both sides, we get

64 + (y + 3)² = 100

(y + 3)² = 36

y + 3 = √36

y + 3 = ± 6

y + 3 = 6 or y + 3 = - 6

Therefore, y = 3 or - 9 are the possible values for y.

☛ Check: NCERT Solutions for Class 10 Maths Chapter 7

Video Solution:

Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.1 Question 8

Summary:

The values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units are y = 3 or - 9.

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