Find the equivalent fraction of 3/5 having
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27
Solution:
We use the concepts of fractions and equivalent fractions to answer the given questions.
Fractions that have the same values irrespective of their numerators and denominators are called equivalent fractions
To obtain the equivalent fractions of 3 / 5, we need to multiply the numerator and denominator by the same numbers.
(a) Denominator 20
To get a fraction with denominator 20, we need to multiply the denominator 3 / 5 by a number that gives 20 as result in the denominator.
3 / 5 × 4 / 4 = 12 / 20.
∴ By multiplying both the numerator and the denominator by 4, we get the required fraction.
(b) Numerator 9
To get a fraction with numerator 9, we need to multiply the numerator 3 / 5 by a number that gives 9 as result in the numerator.
3 / 5 × 3 / 3 = 9 / 15.
∴ By multiplying both the numerator and denominator by 3, we get the required fraction.
(c) Denominator 30
To get a fraction with denominator 30, we need to multiply the denominator of 3 / 5 with a number that gives 30 as result in the denominator.
3 / 5 × 6 / 6 = 18 / 30.
∴ By multiplying both numerator and denominator with 6, we get the required fraction.
(d) Numerator 27
To get a fraction with numerator 27, we need to multiply the numerator 3 / 5 by a number that gives 27 as result in the numerator.
3 / 5 × 9 / 9 = 27 / 45.
∴ By multiplying both the numerator and denominator by 9, we get the required fraction.
NCERT Solutions for Class 6 Maths Chapter 7 Exercise 7.3 Question 4
Find the equivalent fraction of 3/5 having (a) denominator 20 (b) numerator 9 (c) denominator 30 (d) numerator 27
Summary:
The equivalent fractions of 3/5 having (a) denominator 20, (b) numerator 9, (c) denominator 30 and (d) numerator 27 are (a) 12/20 (b) 9/15 (c) 18/30 and (d) 27/45 respectively.
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