Find the area of the shaded region in Fig. 12.21, if ABCD is a square of side 14 cm and APD and BPC are semicircles
Solution:
From figure, it is clear that the diameter of both the semicircles = Side of the square = 14 cm
∴ Radius of each semicircle (r) = 14/2 = 7 cm
Visually, it is clear that
Semicircles APD and BPC are drawn using sides AD and BC respectively as their diameter.
∴ Diameter of each semicircle = 14 cm
Radius of each semicircle (r) = 14/2 = 7 cm
Area of shaded region = Area of square ABCD - (Area of semicircle APD + Area of semicircle BPC)
= (side)2 - (1/2πr2 + 1/2πr2)
= (14)2 - π × (7)2
= 196 cm2 - 22/7 × 7 cm × 7 cm
= 196 cm2 - 154 cm2
= 42 cm2
☛ Check: NCERT Solutions for Class 10 Maths Chapter 12
Video Solution:
Find the area of the shaded region in Fig. 12.21, if ABCD is a square of side 14 cm and APD and BPC are semicircles.
NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.3 Question 3
Summary:
The area of the shaded region in the given figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles is 42 cm2.
☛ Related Questions:
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