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Find the 17th and 24th term of the sequences whose nth term is an = 4n - 3
Solution:
nth term is given as an = 4n - 3
Substituting n = 17
a17 = 4(17) - 3
= 68 - 3 = 65
a17 = 65
Substituting n = 24
a24 = 4 (24) - 3
= 96 - 3
a24 = 93
NCERT Solutions Class 11 Maths Chapter 9 Exercise 9.1 Question 7
Find the 17th and 24th term of the sequences whose nth term is an = 4n - 3
Summary:
We know that the nth term is an = 4n - 3. Therefore the 17th and the 24th term of the sequences are 65 and 93
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