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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Find a point on the x-axis, which is equidistant from the points (7, 6) and (3, 4).
Solution:
Let (a, 0) be the point on the X- axis that is equidistant from the points (7, 6) and (3, 4).
Using distance formula,
√(7 - a)² + (6 - 0)² = √(3 - a)² + (4 - 0)²
⇒ √49 + a² - 14a + 36 = √9 + a² - 6a + 16
⇒ √a² - 14a + 85 = √a² - 6a + 25
On squaring on both sides, we obtain
a2 - 14a + 85 = a2 - 6a + 25
⇒ - 14a + 6a = 25 - 85
⇒ - 8a = 60
⇒ a = 60/8
⇒ a = 15/2
Thus, the required point on the x-axis is (15/2, 0)
NCERT Solutions Class 11 Maths Chapter 10 Exercise 10.1 Question 4
Find a point on the x-axis, which is equidistant from the points (7, 6) and (3, 4)
Summary:
The point on the x-axis, which is equidistant from the points (7, 6) and (3, 4) is (15/2, 0)
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