Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?
Solution:
For Simple Interest:
A = (P × R × T)/100
P = ₹ 12,500
T = 3 years
R = 12% simple interest
where , A = Amount, P = Principal, T = Time period in years and R = Rate percent
Thus, Simple Interest paid by Fabina for 3 years at the rate of 12% per annum
S.I. for 3 years = (3 × 12500 × 12)/100
= 3 × 125 × 12
= 4500
For Compound Interest:
A = P[1 + (r/100)]n
P = ₹ 12,500
n = 3 years
R = 10% compounded annually
Thus, Amount paid by Radha for 3 years at the rate of 10% p.a. compounded annually
A = P[1 + (r/100)]n
A = 12500[1 + (10/100)]3
A = 12500(11/10)3
A = 12500 × (11/10) × (11/10) × (11/10)
A = 12500 × (1331/1000)
A = 12500 × 1.331
A = 16637.50
Compound Interest = A - P
= 16637.50 - 12500
= 4137.50
Since 4500 > 4137.50, Fabina paid more interest than Radha.
Additional Interest paid by Fabina = 4500 – 4137.50 = ₹ 362.50
☛ Check: NCERT Solutions for Class 8 Maths Chapter 8
Video Solution:
Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?
NCERT Solutions Class 8 Maths Chapter 8 Exercise 8.3 Question 3
Summary:
Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Fabina pays more interest and by ₹ 362.50.
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