Estimate each of the following using general rules:
(a) 730 + 998 (b) 796 - 314 (c) 12904 + 2888 (d) 28292 - 21496
Make ten more such examples of addition, subtraction, and estimation of their outcome

Solution:

We will be using the concept of estimation in math to solve this problem.

(a) 730 + 998
Nearest round off of 730 = 700
Nearest round off of 998 = 1000
Sum of 730 + 998 = 700 + 1000 = 1700
(b) 796 - 314
Nearest round off of 796 = 800
Nearest round off 314 = 300
Subtraction of 796 - 314 = 800 - 300 = 500
(c) 12904 + 2888
Nearest round off of 12904 = 13000
Nearest round off of 2888 = 3000
Sum of 12904 + 2888 = 13000 + 3000 = 16000
(d) 28292 - 21496
Nearest round off of 28292 = 28000
Nearest round off of 21496 = 21000
Subtraction of 28292 - 21496 = 28000 - 21000 = 7000

Ten more such examples are
(i) 435 + 282 = 400 + 300 = 700
(ii) 3986 + 5870 = 4000 + 6000 = 10000
(iii) 7392 - 4789 = 7000 - 5000 = 2000
(iv) 5160 - 2792 = 5000 - 3000 = 2000
(v) 2195 + 1306 = 2000 + 1000 = 3000
(vi) 1180 - 1382 = 1000 - 1000 = 0
(vii) 920 + 565 = 900 + 600 = 1500
(viii) 6410 - 4860 = 6000 - 5000 = 1000
(ix) 3841 + 1450 = 4000 + 1000 = 5000
(x) 6375 - 4229 = 6000 - 4000 = 2000

NCERT Solutions Class 6 Maths Chapter 1 Exercise 1.3 Question 1

Estimate each of the following using general rule:(a) 730 + 998 (b) 796 - 314 (c) 12904 + 2888 (d) 28292 - 21496. Make ten more such examples of addition, subtraction and estimation of their outcome

Summary:

(a) 730 + 998 can be estimated as the sum of their nearest rounded off numbers such that, 700 + 1000 = 1700 (b) 796 - 314 can be estimated as the difference of their nearest rounded off numbers such that, 800 - 300 = 500 (c) 12904 + 2888 can be estimated as the sum of their nearest rounded off numbers such that, 13000 + 3000 = 16000 (d) 28292 - 21496 can be estimated as the difference of their nearest rounded off numbers such that, 28000 - 21000 = 7000.

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