Determine the probability that tomorrow’s output will have more than 13 defective parts? Over the past 200 working days, the number of defective parts produced by a machine is given in the following table:
Number of defective parts 0 1 2 3 4 5 6 7 8 9 10 11 12 13
Days 50 32 22 18 12 12 10 10 10 8 6 6 2 2
Solution:
Given, the table represents the number of defective parts produced by a machine over the past 200 working days.
We have to determine the probability that tomorrow’s output will have more than 13 defective parts.
Probability of an event = Number of trials in which the event has happened / Total number of trials
From the given table,
Number of days which has more than 13 defective parts = 0
So, the number of trials in which the event has happened = 0
Total number of trials = 200
Probability that tomorrow’s output will have more than 13 defective parts = 0/200
= 0
Therefore, the probability that tomorrow’s output will have more than 13 defective parts is 0.
✦ Try This: Over the past 300 working days, the number of defective parts produced by a machine is given in the following table:
Number of defective parts | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
Days | 100 | 32 | 22 | 18 | 12 | 12 | 20 | 20 | 25 | 8 | 11 | 11 | 7 | 2 |
Determine the probability that tomorrow’s output will have not more than 6 defective parts.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 14
NCERT Exemplar Class 9 Maths Exercise 14.3 Problem 19(iv)
Determine the probability that tomorrow’s output will have more than 13 defective parts? Over the past 200 working days, the number of defective parts produced by a machine is given in the following table: Number of defective parts 0 1 2 3 4 5 6 7 8 9 10 11 12 13 Days 50 32 22 18 12 12 10 10 10 8 6 6 2 2
Summary:
Over the past 200 working days, the number of defective parts produced by a machine is given in the table. The probability that tomorrow’s output will have more than 13 defective parts is 0
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