Determine, graphically, the vertices of the triangle formed by the lines y = x, 3y = x, x + y = 8
Solution:
From the above question, we have the equation as,
y = x,
3y = x.
x + y = 8.
Table for line y = x,
|
x |
0 |
1 |
2 |
|---|---|---|---|
|
y |
0 |
1 |
2 |
Table for line x = 3y
|
x |
0 |
3 |
6 |
|---|---|---|---|
|
y |
0 |
1 |
2 |
Table for line x + y = 8
|
x |
0 |
4 |
8 |
|---|---|---|---|
|
y |
8 |
4 |
0 |
Plotting the points we get the graph of given lines.
The lines y = x and 3y = x intersect the line x + y = 8 at Q and D, respectively.
Hence, ∆OQD is formed by these lines.
Therefore the vertices of the ∆OQD are O(0, 0), Q(4, 4), and D(6, 2).
✦ Try This: Determine, graphically, the vertices of the triangle formed by the lines y = 2x, 3y = x, x + y = 6
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3
NCERT Exemplar Class 10 Maths Exercise 3.4 Problem 2
Determine graphically, the vertices of the triangle formed by the lines y = x, 3y = x, x + y = 8
Summary:
Graphically the vertices of the triangle formed by the lines y = x, 3y = x, x + y = 8 is O(0, 0), Q(4, 4) and D(6, 2)
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