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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm
Solution:
To construct a right-angled ΔPQR, where ∠Q = 90°, QR = 8cm, and PR = 10cm, draw a rough sketch for your reference and mark the measures.
Remember to mark the right angle and follow the steps given below.
Steps of construction:
- Draw a line segment QR of length 8 cm.
- At Q, draw QX perpendicular QR.
- With R as the center, draw an arc of radius 10cm which should intersect QX at point P.
- Join P and R.
- ΔPQR is the required triangle.
☛ Check: NCERT Solutions for Class 7 Maths Chapter 10
Video Solution:
Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm
Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.5 Question 1
Summary:
A right angled ∆PQR is constructed, where m∠Q = 90°, QR = 8cm and PR = 10 cm.
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