Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm

Solution:

To construct a right-angled ΔPQR, where ∠Q = 90°, QR = 8cm, and PR = 10cm, draw a rough sketch for your reference and mark the measures.

Remember to mark the right angle and follow the steps given below.

Steps of construction:

1. Draw a line segment QR of length 8 cm.
2. At Q, draw QX perpendicular QR.
3. With R as the center, draw an arc of radius 10cm which should intersect QX at point P.
4. Join P and R.
5. ΔPQR is the required triangle.

☛ Check: NCERT Solutions for Class 7 Maths Chapter 10

Video Solution:

Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.5 Question 1

Summary:

A right angled ∆PQR is constructed, where m∠Q = 90°, QR = 8cm and PR = 10 cm.

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