Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°

Solution:

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

To construct a ΔDEF, first, we draw a rough sketch with the given measure such that DE = 5cm, DF = 3cm and ∠EDF = 90° for our reference, then follow the steps given below.

Steps of construction :

1. Draw a line segment DE of length 5 cm.
2. At D, draw a ray DX making 90° with DE.
3. With D as the center, draw an arc of radius 3cm to cut DX at point F.
4. Join EF to get the required triangle.
5. Thus,​​​​​​ ΔDEF  is the required triangle.  

☛ Check: NCERT Solutions for Class 7 Maths Chapter 10

Video Solution:

Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.3 Question 1

Summary:

∆DEF is constructed such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

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