Construct a trapezium ABCD where AB||CD, AD = BC = 3.2cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.
[Hint : Difference of two parallel sides gives an equilateral triangle.]

Solution:

Given, ABCD is a trapezium in which AB || CD.

AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm.

We have to construct a trapezium ABCD and find the measure of ∠B and ∠A.

To construct a trapezium ABCD,

1. Draw a line segment DC = 9.6 cm

2. With D as center, draw an angle which measures 60°. Now, cut off it with an arc 3.2cm cm called point A.

3. Draw a line AB parallel to CD

4. Taking C as center, cut an arc B measuring 3.2 cm on the previous parallel line.

5. Draw a line segment BE = 3.2 cm from arc B

6. Join B to E and C

The measure of ∠A = 120° and ∠B = 60°.

Therefore, ABCD is the required trapezium.

✦ Try This: Construct a trapezium ABCD in which AB is parallel to DC, AB = 7 cm, BC = 5 cm, CD = 4 cm and AD = 5 cm and calculate its area.

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 5 Problem 203

Construct a trapezium ABCD where AB||CD, AD = BC = 3.2cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A. [Hint : Difference of two parallel sides gives an equilateral triangle.]

Summary:

A trapezium ABCD where AB||CD, AD = BC = 3.2cm, AB = 6.4 cm and CD = 9.6 cm is constructed . Measure ∠B and ∠A are 60° and 120°.

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