An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer
Solution:
From the values given, the figure is
We know that
Tan A = Opposite side to angle A/Adjacent side
tan A = OB/BC
From the figure,
OB = 22 - 1.5 = 20.5 meters
BC = 20.5
So we get
tan A = 20.5/20.5 = 1 …….(i)
By trigonometric values
tan 45° = 1 ……..(ii)
From both the equations we get
A = 45°
Therefore, the angle of elevation is 45°.
✦ Try This: A boy 1.7 m tall, is 25 m away from a tower and observes the angle of elevation of the top of the tower to be 60°. Find the height of the tower. a. 55 m, b. 45 m, c. 20 m, d. 35 m
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 8
NCERT Exemplar Class 10 Maths Exercise 8.3 Problem 14
An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer
Summary:
An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. The angle of elevation of the top of the tower from the eye of the observer is 45°
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