A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
(i) the area of the verandah
(ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m²

Solution:

Let's represent the situation diagrammatically as shown below.

Let the blue region represent the room and the yellow region represent the verandah.

Area of the room = Length × Breadth

= 5.5 m × 4 m

= 22 m²

Length of the room including veranda = 5.5 m + (2.25 × 2) m

= 5.5 m + 4.5 m

= 10 m

Breadth of the room including veranda = 4 m + (2.25 × 2) m

= 4 m + 4.5 m

= 8.5 m

Area of the room including veranda = Length × Breadth

= 10 m × 8.5 m

= 85 m²

(i) Area of the veranda = Area of the room including veranda - Area of the room

= 85 cm² - 22 cm²

= 63 m²

(ii) The cost of cementing 1 m² floor of the veranda = Rs.200

The cost of cementing 63 m² floor of the veranda = Rs.200 × 63

= Rs.12600

☛ Check: NCERT Solutions for Class 7 Maths Chapter 11

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Video Solution:

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah. (ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m²

Maths NCERT Solutions Class 7 Chapter 11 Exercise 11.4 Question 4

Summary:

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Then: (i) the area of the verandah is 63 m². (ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m² is ₹12600.

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