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A student says that if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting ‘not 1’ each is equal to 1/2 . Is this correct? Give reasons

Solution:

If a die is thrown, total number of outcomes = 6

Possible outcomes = 1, 2, 3, 4, 5, 6

We know that

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

Probability = Favourable outcomes/ Total outcomes

So the probability of getting 1 = 1/6

Probability of getting ‘not 1’ = 1 - probability of getting 1

Substituting the values

= 1 - 1/6

= 5/6

Therefore, the statement is not correct.

✦ Try This: When a die is thrown, the probability of getting an even number less than 4 is

A die has the shape of a cube with six faces

Each face is marked as 1, 2, 3, 4, 5, and 6 dots

We know that

Even number is the number which is divisible by 2

Even numbers = 3 {2, 4, 6}

Even numbers less than 4 = 1 {2}

Total outcome = 6 {1, 2, 3, 4, 5, 6}

So the probability of getting an even number which is less than 4 = Number of favourable outcomes/ Total outcomes

Substituting the values

= 1/6

Therefore, the probability of getting an even number less than 4 is 1/6.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14

NCERT Exemplar Class 10 Maths Exercise 13.2 Problem 9

A student says that if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting ‘not 1’ each is equal to 1/2 . Is this correct? Give reasons

Summary:

The statement “A student says that if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting ‘not 1’ each is equal to 1/2” is not correct

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