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A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days, and an additional charge for each day thereafter. Latika paid Rs 22 for a book kept for six days, while Anand paid Rs 16 for the book kept for four days. Find the fixed charges and the charge for each extra day

Solution:

₹ x is the fixed charge for the first two days

₹ y is the additional charge for each.

From the first condition,

Latika paid ₹ 22 for a book kept for six days

x + 4y = 22---------(1)

According to the second condition,

Anand paid ₹16 for a book kept for four days

x + 2y = 16------------(2)

Now solve equations (1) and (2)

Subtracting (2) from (1), we get,

2y = 6

y = 3.

Substitute the value of y in (2), we get,

x + 2 x 3 = 16

x = 16 - 6 = 10

x = 10.

y = 3.

Therefore, the fixed charge = ₹ 10 and the charge for each extra day = ₹ 3.

✦ Try This: A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days, and an additional charge for each day thereafter. Latika paid Rs 44 for a book kept for six days, while Anand paid Rs 24 for the book kept for four days. Find the fixed charges and the charge for each extra day

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.3 Problem 20

A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days, and an additional charge for each day thereafter. Latika paid Rs 22 for a book kept for six days, while Anand paid Rs 16 for the book kept for four days. Find the fixed charges and the charge for each extra day

Summary:

A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days, and an additional charge for each day thereafter. Latika paid Rs 22 for a book kept for six days, while Anand paid Rs 16 for the book kept for four days. The fixed charges and the charge for each extra day is ₹ 10 and ₹ 3.

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