A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm. Find the cost of covering the floor with tiles at the rate of ₹ 4.50 per tile.

Solution:

It is given that

Length of room = 4.5 m

Width of room = 4 m

Size of tiles = 15 cm × 10 cm

We know that

Area of room = l × b

Substituting the values

= 4.5 × 4

= 18 m²

As 1 m = 100 cm

= 18 × 100²

= 180000 cm²

As the area of 1 tile is 15 × 10 = 150 cm²

Number of tiles = Area of room/ Area of 1 tile

Substituting the values

= 180000/150

= 1200

Given

Cost of covering the floor with tiles = ₹ 4.50 × 1200

= ₹ 5400

Therefore, the cost of covering the floor with tiles at the rate of ₹ 4.50 per tile is ₹ 5400.

✦ Try This: A room is 5.5 m long and 5 m wide. The floor of the room is to be covered with tiles of size 20 cm by 15 cm. Find the cost of covering the floor with tiles at the rate of ₹ 5.50 per tile.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11

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NCERT Exemplar Class 7 Maths Chapter 9 Problem 106

A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm. Find the cost of covering the floor with tiles at the rate of ₹ 4.50 per tile.

Summary:

A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm. The cost of covering the floor with tiles at the rate of ₹ 4.50 per tile is ₹ 5400

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