A hollow cube of internal edge 22cm is filled with spherical marbles of diameter 0.5 cm and it is assumed that 1/8 space of the cube remains unfilled. Then the number of marbles that the cube can accomodate is
a. 142296
b. 142396
c. 142496
d. 142596
Solution:
It is given that
The internal edge of a hollow cube = 22 cm
Volume of cube = side³ = 22³ = 10648 cm³
Diameter of special marbles = 0.5 cm
Radius of special marbles = 0.5/2 = 1/4 cm
We know that
Volume of one marble = 4/3 πr³
Substituting the values
Volume of one marble = 4/3 × 22/7 × (1/4)³
= 11/168 cm³
Here
Filled space of the cube = Volume of cube - 1/8 volume of cube
= 10648 - 1/8 × 10648
= 10648 × 7/8
= 9317 cm³
So the required number of marbles = total space filled by the marble in one cube/ volume of one marble
= 9317/ (11/168)
= 142296
Therefore, the number of marbles that the cube can accomodate is 142296.
✦ Try This: A hollow cube of internal edge 24cm is filled with spherical marbles of diameter 0.4 cm and it is assumed that 1/5 space of the cube remains unfilled. Then the number of marbles that the cube can accomodate is
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 13
NCERT Exemplar Class 10 Maths Exercise 12.1 Problem 8
A hollow cube of internal edge 22cm is filled with spherical marbles of diameter 0.5 cm and it is assumed that 1/8 space of the cube remains unfilled. Then the number of marbles that the cube can accomodate is a. 142296, b. 142396, c. 142496, d. 142596
Summary:
A hollow cube of internal edge 22cm is filled with spherical marbles of diameter 0.5 cm and it is assumed that 1/8 space of the cube remains unfilled. Then the number of marbles that the cube can accomodate is 142296
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