A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 15.5 ), and these are equally likely outcomes. What is the probability that it will point at
(i) 8 ?
(ii) an odd number?
(iii) a number greater than 2?
(iv) a number less than 9?
Solution:
We know that,
Probability = Number of possible outcomes/Total number of favorable outcomes.
Total possible outcomes = 8
(i) Probability of getting 8 = Probability of getting 8 / Total number of outcomes
Probability of getting 8 = 1/8
(ii) Total number of odd numbers = 1, 3, 5, 7 = 4
Probability of getting odd number = Total number of odd numbers/Total number of outcomes
= 4/8 = 1/2
(iii) The numbers that are greater than 2 are 3, 4, 5, 6, 7, 8 = 6
Probability of getting numbers greater than 2 = Numbers greater than 2/Total number of outcomes
= 6/8
= 3/4
(iv) The numbers less than 9 are 1, 2, 3, 4, 5, 6, 7, 8 = 8
Probability of getting numbers less than 9 = Numbers lesser than 9/Total number of outcomes
= 8/8 = 1
Check out more on the terms of probability.
☛ Check: NCERT Solutions for Class 10 Maths Chapter 15
Video Solution:
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 15.5 ), and these are equally likely outcomes. What is the probability that it will point at (i) 8 ? (ii) an odd number? (iii) a number greater than 2? (iv) a number less than 9?
NCERT Solutions for Class 10 Maths Chapter 1 Exercise 15.1 Question 12
Summary:
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8, and these are equally likely outcomes. The probability that it will point at 8, an odd number, a number greater than 2, and a number less than 9 are 1/8, 1/2, 3/4, and 1 respectively.
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