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A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs. 23.25. What will be the cost to cover the floor with these tiles

Solution:

Length of the floor = 4.5 m

Converting 4.5 m into cm = 4.5 × 100 = 450 cm

Width of the floor = 3.6m

Converting 3.6 m into cm = 3.6 × 100 = 360 cm

Area of the floor = (450 × 360) = 162000 cm. Sq.

Side of one square tile = 6 cm

Area of one square tile = 36 sq. cm.

Number of tiles required to cover the floor = Area of floor ÷ Area of one tile

= 162000 ÷ 36

=4500

It is given that the cost of one tile = ₹ 23.25

Cost of 4500 tiles = ₹ 23.25 × 4500 = ₹ 104625

✦ Try This: A floor is 7.5 m long and 3.6 m wide. A 4 cm square tile costs rupees 24.25. What will be the cost to cover the floor with these tiles?

To solve the above problem you can follow the fractions and decimals rules to get the required answer.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 2

NCERT Exemplar Class 7 Maths Chapter 2 Exercise Problem 87

The floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs. 23.25. What will be the cost to cover the floor with these tiles

Summary:

The floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs. 23.25. The cost to cover the floor with 4500 tiles is ₹ 104625

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