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A day full of math games & activities. Find one near you.
A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14)
Solution:
Diameter of the circular flower bed = 66 m
Radius of circular flower bed (r) = 66/2 m = 33 m
Radius of circular flower bed with 4 m wide path (R) = 33 m + 4 m = 37 m
Area of path = Area of bigger circle – Area of smaller circle
= πR2 - πr2
= π(R2 - r2 )
= 3.14 (37 m2 - 33 m2)
= 3.14 × (37 + 33) (37 – 33)
= 3.14 × 70 m × 4 m
= 879.20 m2
☛ Check: NCERT Solutions for Class 7 Maths Chapter 11
Video Solution:
A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?
Maths NCERT Solutions Class 7 Chapter 11 Exercise 11.3 Question 13
Summary:
A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. The area of this path is 879.20 m2.
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