A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?
Solution:
We will use the basic concepts of probability to solve the problem.
This question can be solved by using two steps.
Step (i): First find out the probability of drawing a red ball by using the formula given below.
Probability of an event = Number of possible outcomes/total number of favourable outcomes
Step (ii): After that, by using the formula for the sum of complementary event, find the probability of not getting a red ball.
P (E) + P (not E) = 1
(i) Number of red balls in a bag = 3
Number of black balls in a bag = 5
Total number of balls = 3 + 5 = 8
Probability of drawing red ball P(E) = Number of possible outcomes/Total number of favourable outcomes
Probability of drawing red ball = 3/8
(ii) Probability of not getting red ball P(not E) = 1 - P (E) = 1 - 3/8 = 5/8
☛ Check: NCERT Solutions for Class 10 Maths Chapter 15
Video Solution:
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?
NCERT Solutions for Class 10 Maths Chapter 15 Exercise 15.1 Question 8
Summary:
If a bag contains 3 red balls and 5 black balls, and a ball is drawn at random from the bag, then the probability that the ball drawn is red is 3/8 and the probability that the ball drawn is not red is 5/8.
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